Enhanced Client or Proxy Profile Version 2.0, can Azure AD be used as the IdP?

[Phil Pishioneri]

The description on that Okta page ("Complete software solutions for 
Assisted Living, Independent Living, Group and DD homes") sounds like a 
match for this "ECP" company's (Extended Care Professional) services:

https://www.ecp123.com/independent-living

-Phil


On 2022/4/19 12:40 PM, Wessel, Keith via users wrote:
> Amazingly, Okta claims they do. Can't say if it actually works.
>
> This page is very vague:
>
> https://www.okta.com/integrations/ecp/
>
> But there are plenty of other references in their docs to ECP.
>
> Scary stuff...
>
> I, too, would be very surprised if Azure AD supported ECP, though. They've mostly adopted OIDC and "sign into work or school" flows for getting the credentials in place to support non-browser interactions. Looks like some folks have asked in the MSDN forums but gotten nothing in terms of helpful responses. There's probably a reason that those of us using Azure AD and ADFS are proxying through Shib to get there: Shib can still enforce the ECP endpoints.
>
> Keith
>
>
> -----Original Message-----
> From: users <users-bounces at shibboleth.net> On Behalf Of Cantor, Scott via users
> Sent: Tuesday, April 19, 2022 11:22 AM
> To: Shib Users <users at shibboleth.net>
> Cc: Cantor, Scott <cantor.2 at osu.edu>
> Subject: Re: Enhanced Client or Proxy Profile Version 2.0, can Azure AD be used as the IdP?
>
> On 4/19/22, 11:58 AM, "users on behalf of Paul B Hill via users" <users-bounces at shibboleth.net on behalf of users at shibboleth.net> wrote:
>
>> I realize this is the Shibboleth user’s list and this is slightly off topic. But, does anyone on the list know if Azure
>> AD may be used as an IDP for applications using Enhanced Client or Proxy Profile Version 2.0?
> I have never heard anything to suggest it supports ECP.
>
>> I know that Okta supports this, but so far I have not found any current definitive statements about Azure AD.
> I seriously doubt Okta supports ECP. Maybe I'm wrong.
>
> -- Scott
>
>